63x^2=27x

Solution for 63x^2=27x equation:

63x^2=27x

We move all terms to the left:

63x^2-(27x)=0

a = 63; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·63·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*63}=\frac{0}{126}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*63}=\frac{54}{126}
=3/7
$